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Mycat中如何配置schmea.xml

2025-06-24 08:03来源:互联网 [ ]

1.基本环境dn1localhost1192.168.6.121:3306---writehost
192.168.6.121:3307---readhost
192.168.6.121:3308dn2locahost2192.168.6.120:3306---writehost
192.168.6.120:3307---readhost
192.168.6.121:3308dn3localhost3192.168.6.119:3306---writehost
192.168.6.119:3307---readhost
192.168.6.119:3308



2.schemal配置

    <?xml version="1.0"?>

    <!DOCTYPE mycat:schema SYSTEM "schema.dtd">

    <mycat:schema xmlns:mycat="http://io.mycat/">

    <schema name="TESTDB" checkSQLschema="false" sqlMaxLimit="100" dataNode="dn1">---默认数据节点,若新建一张表company2未在配置文件中配置,则默认建立在dn1数据节点上(私有表)

    <!-- auto sharding by id (long) -->

    <table name="travelrecord" dataNode="dn1,dn2,dn3" rule="auto-sharding-long" />---分片表,根据对应的分片规则 分片到各个物理节点上

    <!-- global table is auto cloned to all defined data nodes ,so can join

    with any table whose sharding node is in the same data node -->

    <table name="company" primaryKey="ID" type="global" dataNode="dn1,dn2,dn3" />---全局表,每个节点上都有的表

    ---等同于company

    ----等同于company2

    <table name="goods" primaryKey="ID" type="global" dataNode="dn1,dn2,dn3" />

    <!-- random sharding using mod sharind rule -->

    <table name="hotnews" primaryKey="ID" autoIncrement="true" dataNode="dn1,dn2,dn3"

    rule="mod-long" />

    <!-- <table name="dual" primaryKey="ID" dataNode="dnx,dnoracle2" type="global"

    needAddLimit="false"/> <table name="worker" primaryKey="ID" dataNode="jdbc_dn1,jdbc_dn2,jdbc_dn3"

    rule="mod-long" /> -->

    <table name="employee" primaryKey="ID" dataNode="dn1,dn2"

    rule="sharding-by-intfile" />

    <table name="customer" primaryKey="ID" dataNode="dn1,dn2"

    rule="sharding-by-intfile">

    <childTable name="orders" primaryKey="ID" joinKey="customer_id"

    parentKey="id">

    <childTable name="order_items" joinKey="order_id"

    parentKey="id" />

    </childTable>

    <childTable name="customer_addr" primaryKey="ID" joinKey="customer_id"

    parentKey="id" />

    </table>

    <!-- <table name="oc_call" primaryKey="ID" dataNode="dn1$0-743" rule="latest-month-calldate"

    /> -->

    </schema>

    <!-- <dataNode name="dn1$0-743" dataHost="localhost1" database="db$0-743"

    /> -->


      <dataNode name="dn1" dataHost="localhost1" database="examdb" /> ----数据节点对应的localhost以及真实的数据库

      <dataNode name="dn2" dataHost="localhost2" database="examdb" />

      <dataNode name="dn3" dataHost="localhost3" database="examdb" />

      <dataHost name="localhost1" maxCon="1000" minCon="10" balance="2"------localhosts对应的连接配置信息

      writeType="0" dbType="mysql" dbDriver="native" switchType="1" slaveThreshold="100">

      <heartbeat>select user()</heartbeat>

      <!-- can have multi write hosts -->

      <writeHost host="hostM1" url="192.168.6.121:3306" user="root"

      password="ESBecs00">

      <!-- can have multi read hosts -->

      </writeHost>

      </dataHost>

      <dataHost name="localhost2" maxCon="1000" minCon="10" balance="2"

      writeType="0" dbType="mysql" dbDriver="native" switchType="1" slaveThreshold="100">

      <heartbeat>select user()</heartbeat>

      <!-- can have multi write hosts -->

      <writeHost host="hostM1" url="192.168.6.120:3306" user="root"

      password="ESBecs00">

      <!-- can have multi read hosts -->

      </writeHost>

      </dataHost>

      <dataHost name="localhost3" maxCon="1000" minCon="10" balance="2"

      writeType="0" dbType="mysql" dbDriver="native" switchType="1" slaveThreshold="100">

      <heartbeat>select user()</heartbeat>

      <!-- can have multi write hosts -->

      <writeHost host="hostM1" url="192.168.6.119:3306" user="root"

      password="ESBecs00">

      <!-- can have multi read hosts -->

      </writeHost>

      </dataHost>

      </mycat:schema>

      ......未完待续


    全局表的查询有负载均衡的作用

      mysql> select * from company;----本应该是相同的数据,改为不同的数据是为了展示负载均衡的效果

      +----+-------------+

      | id | name |

      +----+-------------+

      | 1 | this is 119 |

      +----+-------------+

      1 row in set (0.01 sec)

      mysql> select * from company;

      +----+-------------+

      | id | name |

      +----+-------------+

      | 1 | this is 120 |

      +----+-------------+

      1 row in set (0.01 sec)

      mysql> select * from company;

      +----+-------------+

      | id | name |

      +----+-------------+

      | 1 | this is 121 |

      +----+-------------+

      1 row in set (0.00 sec)


    分片表和私有表如果不在一哥节点上就联合查不到了!

    uc分片表,4101在第二个节点上
    act为私有表,4101在第一个节点上
    select * from uc_coupon where COUPON_ID=4101 ;--单独查,是有的
    select * from act_vote_info where id=4101;---单独查,是有的
    select a.*,b.* from uc_coupon a,act_vote_info b where a.COUPON_ID=b.id and b.id=4101 limit 1; --联合查,查不到了,因为跨节点了!
    举例:

      mysql> select * from order2;---分片表

      +----+----------+---------+---------------------+

      | ID | PROVINCE | SN | CREATE_TIME |

      +----+----------+---------+---------------------+

      | 2 | shanghai | 2BJ0001 | 2017-05-09 15:01:33 |---节点2上

      | 1 | beijing | 2BJ0001 | 2017-04-23 21:48:08 | ---节点1上

      | 3 | tianjin | 2BJ0001 | 2017-05-09 15:01:45 |

      +----+----------+---------+---------------------+

      3 rows in set (0.00 sec)

      mysql> select * from tt;---私有表 节点1上

      +------+------------+

      | id | name |

      +------+------------+

      | 2 | zhangsanli |

      | 1 | 12314 |

      +------+------------+

      2 rows in set (0.00 sec)

      mysql> select a.*,b.* from tt a,order2 b where a.id=b.ID and b.id=2;-----2和私有表不在一个节点上,查不出来

      Empty set (0.00 sec)

      mysql> select a.*,b.* from tt a,order2 b where a.id=b.ID and b.id=1;-----1和私有表在一个节点上,所以查的出来

      +------+-------+----+----------+---------+---------------------+

      | id | name | ID | PROVINCE | SN | CREATE_TIME |

      +------+-------+----+----------+---------+---------------------+

      | 1 | 12314 | 1 | beijing | 2BJ0001 | 2017-04-23 21:48:08 |

      +------+-------+----+----------+---------+---------------------+

      1 row in set (0.00 sec)


    同理:

    分片表和分片表条件数据如果不在一个节点上就联合查不到了!

      mysql> select a.* ,b.* from order2 a,order3 b where a.id=b.id and a.id=2;--单独都是有数据的,但是id相等的分在不同的节点上,还是不能跨节点

      Empty set (0.00 sec)

    mysql> select * from order2;
    +----+----------+---------+---------------------+
    | ID | PROVINCE | SN | CREATE_TIME |
    +----+----------+---------+---------------------+
    | 2 | shanghai | 2BJ0001 | 2017-05-09 15:01:33 |
    | 1 | beijing | 2BJ0001 | 2017-04-23 21:48:08 |
    | 3 | tianjing | 2BJ0001 | 2017-05-15 14:52:17 |
    +----+----------+---------+---------------------+
    3 rows in set (0.00 sec)


    mysql> select * from order3;
    +----+----------+---------+---------------------+
    | ID | PROVINCE | SN | CREATE_TIME |
    +----+----------+---------+---------------------+
    | 2 | beijing | 2BJ0001 | 2017-05-15 14:56:27 |
    | 1 | tianjing | 2BJ0001 | 2017-05-15 14:56:35 |
    | 3 | shanghai | 2BJ0001 | 2017-05-15 14:56:17 |
    +----+----------+---------+---------------------+
    3 rows in set (0.00 sec)

    解决办法:注解,详细用法见文档

      mysql> /*!mycat:catlet=demo.catlets.ShareJoin */ select b.sn,b.CREATE_TIME,a.CREATE_TIME from order2 a,order3 b where a.id=b.id;

      +---------------------+----+---------+---------------------+

      | CREATE_TIME | id | sn | CREATE_TIME |

      +---------------------+----+---------+---------------------+

      | 2017-04-23 21:48:08 | 1 | 2BJ0001 | 2017-05-15 14:56:35 |

      | 2017-05-09 15:01:33 | 2 | 2BJ0001 | 2017-05-15 14:56:27 |

      | 2017-05-15 14:52:17 | 3 | 2BJ0001 | 2017-05-15 14:56:17 |

      +---------------------+----+---------+---------------------+